wwDotNetBridge::FromXml - West Wind Web Connection

wwDotNetBridge::FromXml

Parses an XML string into a .NET object.

This method requires that you provide either .NET type object, or a fully qualified type name (namespace.classname or fully qualified GAC name).

o.FromXml(lcJson,lvDotnetType)

Parameters

lcJson
Xml String. Should be in same format as data returned from ToXml()

lvDotnetType
The type of the object to be deserialized into. Accepts a .NET Type object (use GetType or GetTypeFromName) or a fully qualified class name (Namespace.Class)

Remarks

XML must be in the same format as what ToXml() creates.

<?xml version="1.0" encoding="utf-8"?>
<TestCustomer xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
   <Name>Rick</Name>
   <Company>Westwind</Company>
   <Entered>2013-02-03T17:24:26</Entered>
   <Number>100.21</Number>
   <Address>
      <Street>32 Kaiea</Street>
      <City>Paia</City>
   </Address>
</TestCustomer>

The XML header is not required. If types are simple and well known the namespaces may also not required.

Example

loBridge = GetwwDotnetBridge()

*** Create XML
loCust = loBridge.CreateInstance("Westwind.WebConnection.TestCustomer")
loCust.Name = "Rick"
loCust.Company = "Westwind"
loCust.Number = 100.21
loCust.Entered = DATETIME()
loCust.Address.Street = "32 Kaiea Place"
loCust.Address.City = "Paia"

*** Serialize to XML string
lcXml = loBridge.ToXml(loCust)
? lcXml
loCust = null

*** Deserialize back to object
loCust2 = loBridge.FromXml(lcXml,"Westwind.WebConnection.TestCustomer")
? loBridge.cErrorMsg
? loCust2.Company 
? loCust2.Address.City

Parameters

Remarks

Example

See also: